-16x^2+176x+135=0

Solution for -16x^2+176x+135=0 equation:

-16x^2+176x+135=0

a = -16; b = 176; c = +135;
Δ = b2-4ac
Δ = 1762-4·(-16)·135
Δ = 39616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{39616}=\sqrt{64*619}=\sqrt{64}*\sqrt{619}=8\sqrt{619}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(176)-8\sqrt{619}}{2*-16}=\frac{-176-8\sqrt{619}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(176)+8\sqrt{619}}{2*-16}=\frac{-176+8\sqrt{619}}{-32}
$